A chlorine concentration of 0.500 ppm is desired for water purification. What mass of chlorine must be added to 2500 L of water to achieve this level?

1.25 grams of chlorine.

Explanation:

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In this case, since it is possible to define the parts per million of chlorine as the milligrams of chlorine per liters of water, in order to obtain the mass of chlorine in 2500 L, we proceed as follows:

In such a way, we plug in the given 0.500 ppm and 2500 L to obtain (in grams):

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explanation:

0.07 g/cm³

1.37 g/cm³

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.