When there are 165.0grams of reactants, what is the mass of the products for that reaction?

165.0 grams

Explanation:

The law of conservation of mass tells us that the mass of the reactants will be equal to the mass of the products. Therefore, if we begin with 165.0 grams of mass, that is how much there will be at the end in the products, even if it's in different forms.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.