An oxygen molecule is adsorbed on a patch of surface (see sketch at right). This patch is known to contain adsorption sites. The molecule has enough energy to move from site to site, so it could be on any one of them. Suppose part of the surface becomes inaccessible, so that only adsorption sites are now available for the molecule. Calculate the change in entropy. Round your answer to significant digits, and be sure it has the correct unit symbol.

This question is incomplete, the complete question is;

An oxygen  (O₂) molecule is adsorbed on a patch of surface (see sketch at right). This patch is known to contain 324 adsorption sites.

The  (O₂) molecule has enough energy to move from site to site, so it could be on any one of them.

Suppose part of the surface becomes inaccessible, so that only 400 adsorption sites are now available for the molecule.

Calculate the change in entropy.

Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

the change in entropy is 2.91  x 10⁻²³ J/K

Explanation:

Given the data in the question;

For an ideal gas,

Entropy of a molecule, S = K ln(W)

where K  is Boltzmann constant (1.38065 x 10⁻²³ J/K)

W is Equivalent micro states of the molecule

( W = 324   and W = 400 )

S - S = K ln(W) - K ln(W )

ΔS = K ln(W / W )

we substitute

ΔS = (1.38065 x 10⁻²³ J/K) × ln( 400 / 324 )

ΔS = 2.9093  x 10⁻²³ J/K

ΔS = 2.91  x 10⁻²³ J/K

Therefore,  the change in entropy is 2.91  x 10⁻²³ J/K

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

im not exactly sure but i think its b!