Identify the type of each reaction in the copper cycle. C u S O 4 ( a q ) + Z n ( s ) ⟶ Z n S O 4 ( a q ) + C u ( s ) Choose...
C u ( N O 3 ) 2 ( a q ) + 2 N a O H ( a q ) ⟶ C u ( O H ) 2 ( s ) + 2 N a N O 3 ( a q ) Choose...
C u O ( s ) + H 2 S O 4 ( a q ) ⟶ C u S O 4 ( a q ) + H 2 O ( l ) Choose...
C u ( s ) + 4 H N O 3 ( a q ) ⟶ C u ( N O 3 ) 2 ( a q ) + 2 N O 2 ( a q ) + 2 H 2 O ( l ) Choose...
C u ( O H ) 2 ( s ) Δ −→ C u O ( s ) + H 2 O ( g ) Choose...

CuSO4 (aq) + Zn ( s ) ⟶ ZnSO4 (aq) + Cu (s): single displacement.

Cu(NO3)2(aq) + 2NaOH(aq) ⟶ Cu(OH)2(s) + 2NaNO3 (aq): Double displacement.

CuO(s) + H2SO4 (aq) ⟶ CuSO4 (aq) + H2O( l ): Double displacement.

Cu(s) + 4HNO3 (aq) ⟶ Cu(NO3)2 (aq) + 2NO2(aq) + 2H2O(l): Redox

Cu(OH)2 (s) Δ −→ CuO (s) + H2O(g): Decomposition.

Explanation:

Hello!

In this case, for the given chemical reactions, we obtain:

CuSO4 (aq) + Zn ( s ) ⟶ ZnSO4 (aq) + Cu (s): single displacement as the zinc metal is displacing copper in copper (II) sulfate.

Cu(NO3)2(aq) + 2NaOH(aq) ⟶ Cu(OH)2(s) + 2NaNO3 (aq): Double displacement as sodium is getting with nitrate and copper (II) with hydroxide.

CuO(s) + H2SO4 (aq) ⟶ CuSO4 (aq) + H2O( l ): Double displacement as the oxygen in the cupper (II) oxide turns out with the hydrogen and as a result, copper (II) sulfate is formed.

Cu(s) + 4HNO3 (aq) ⟶ Cu(NO3)2 (aq) + 2NO2(aq) + 2H2O(l): Redox since the copper joins NO3 but at the same time NO2 is released (Nitrogen goes from 5+ to 4+).

Cu(OH)2 (s) Δ −→ CuO (s) + H2O(g): Decomposition as copper (II) hydroxide is separated into copper (II) oxide and water.

Regards!

it is the most commonly accepted one

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explanation: