C6H6 + HNO3 --> C6H5NO2 + H2O The reaction of 36.5 grams of benzene, C6H6, with excess nitric acid resulted in 0.90 grams of water. What is the percent yield?

H = 1.008 amu

C =12.011 amu

N = 14.007 amu

O = 15.999 amu

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

Answerstudying coal cumbustion as an energy source;

Try adding 700% because of the x in y