A saturated solution of NaNO3 is prepared with 100 grams of water at 53 C. What amount of NaNO3 will precipitate if the solution is cooled to 10 C?

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.