What would the rate of the reaction be under the following conditions? (4 points) rate constant = 1.8 * 10 (L/mol)/s
[NO,] = 0.007 M

so what is the problem with your lab report and whats the subject of the lab report? i will you

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.