Mole equations please help me :(

A. 0.48mol O2

Explanation:

The balanced equation is given as follows:

2CH3OH + 3O2 → 2CO2 + 4H2O

This shows that 2moles of CH3OH is required to react with 3 moles of O2

If 0.32 moles of CH3OH are reacted, then;

0.32 × 3/2 moles of O2 is required

= 0.96/2

= 0.48mol of O2

fe 55.85 g/mol and h2o 18.02 g/mol.