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100 g of acetic acid (CH, COOH) is dissolved in a 500.0 ml solution. What is the molarity? Report your answer with the
correct number of significant figures

3.34 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

100 g × 1 mol/60.05 g = 1.67 mol

Step 3: Calculate the molarity of acetic acid

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

M = 1.67 mol/0.5000 L = 3.34 M

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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explanation: