What mass of Fe(OH)3 will be obtained when 100. mL of 0.240 M FeCl3 is mixed with 200. mL of 0.182 M NaOH?

648.68 mg

Explanation:

The reaction that takes place is:

First we calculate how many moles of each reactant were added, using the given volumes and concentrations:

24 mmol of FeCl₃ would react completely with (24 * 3) 72 mmol of NaOH. There are not as many NaOH mmoles, so NaOH is the limiting reactant.

Now we calculate how many moles of Fe(OH)₃ are formed, using the moles of the limiting reactant:

Finally we convert 6.07 mmol Fe(OH)₃ to grams, using its molar mass:

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it's all four options.