Use the following information to calculate the amount of energy (in KJ) required to heat 14.3 g of ethanol from 40oC to 90oC. MW = 46 g/mol

B. P. = 78oC

Heat of vaporization = 841 J/g

specific heat of liquid = 112.4 J/(mol K)

specific heat of gas = 78 J/(mol K)

Round your final answer to a whole number

16

explanation:

the marks go by 4s

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied