How many moles of AgNO3 are needed to produce 6.75 moles of copper (II) nitrate Cu(NO3)2 upon reacting with excess copper (Cu)? 2AgNO3 + Cu --> 2Ag + Cu(NO3)2

Students conversion factor: 6.75 mol Cu(NO3)2 x 1 mol Cu(NO3)2/2 mol AgNO3
Question 1 options:

The student chose the wrong conversion factor.

The student chose the correct conversion factor, but need to flip it to make units cancel.

The student chose the correct conversion factor, but needs to add a second to finish the problem.

There is nothing wrong the problem is ready to be solved.

These questions are based on the attached photo. the experiment is about burning magnesium metal with oxygen. 1. write the balanced chemical equation for the reaction you are performing. 2. calculate the mass of magnesium metal used in each trial. o trial 1: o trial 2: 3. calculate the actual yield of magnesium oxide for each trial. o trial 1: o trial 2: 4. magnesium is the limiting reactant in this experiment. calculate the theoretical yield of mgo for each trial. o trial 1: o trial 2: 5. determine the percent yield of mgo for your experiment for each trial. o trial 1: o trial 2: 6. determine the average percent yield of mgo for the two trials. your company currently uses a process with a similar cost of materials that has an average percent yield of 91 percent. if the average percent yield of this process is higher than that, this could save the company money. what is your recommendation to the company? support your recommendation using your data, calculations, and understanding of stoichiometry gathered from this lab.