A closed gas system initially has pressure and volume of 0.922 atm and 4.64L with the temperature unknown. If the same closed system has values of 1030 torr, 4.36 L, and 837K, what was the initial temperature in K?

606.09K

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the provided information in the question;

P1 = 0.922atm

P2 = 1030torr = 1.355atm

V1 = 4.64L

V2 = 4.36L

T1 = ?

T2 = 837K

Using P1V1/T1 = P2V2/T2

0.922 × 4.64/T1 = 1.355 × 4.36/837

4.278/T1 = 5.9078/837

Cross multiply

5.9078T1 = 837 × 4.278

5.9078T1 = 3580.69

T1 = 3580.69/5.9078

T1 = 606.09K

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023