Use the References to access important values if needed for this question. According to the following reaction, how many moles of sodium hydroxide will be formed upon the complete reaction of 0.263 moles
sodium with excess water?
2Na(s) + 2H, 0() 2NaOH(aq) + H2(g)
mol sodium hydroxide
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0.263 mole of NaOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Na + 2H₂O —> 2NaOH + H₂

From the balanced equation above,

2 moles of Na reacted to produce 2 moles NaOH.

Finally, we shall determine the number of mole of NaOH produced by the reaction of 0.263 mole sodium, Na. This can be obtained as follow:

From the balanced equation above,

2 moles of Na reacted to produce 2 moles NaOH.

Therefore, 0.263 mole of Na will also react to produce 0.263 mole of NaOH.

Thus, 0.263 mole of NaOH was obtained from the reaction.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol