Determine the percent yield for the reaction between 98.7 g of Sb2S3 and excess oxygen gas if 72.4 g of Sb4O6 is recovered along with an unknown amount of sulfur dioxide.

Convert 98.7 g Sb2S3 to mols.
Convert mols Sb2S3 to mols Sb4O6 using the coefficients in the balanced equation.
Convert mols Sb4O6 to grams Sb4O6. (This is the theoretical yield.)
Convert grams Sb4O6 to percent Sb4O6.
%Sb4O6 = [72.4/theoretical yield]*100

So basically your answer is 85.5%

Work done = force ×distancebut force = mass ×gravityand gravity = 10m\s force = 2×10 = 20 work done = 20×3 = 60 joules

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