Use coulomb's law to calculate the ionization energy in kj/mol of an atom composed of a proton and an electron separated by 185.00 pm .

Energy = 752.88 kJ/mol

Explanation:

The force of attraction can be written as:

Integrating to find the expression for energy. We get that:-

Where,  

K is the Coulomb's constant having value 9×10⁹ N. m²/C²

 is the charge on the cation

 is the charge on the anion

e is electronic charge = Charge of the electron = Charge on proton

r is the distance between the cation and anion  = 185.00 pm

Also, 1 pm = 10⁻¹² m

So, r = 185×10⁻¹² m

Applying in the equation,  

Also,

1 atom =

So,

Energy =

Also, 1 J = 0.001 kJ

So, Energy = 752.88 kJ/mol

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g