Calcium carbonate decomposes to form calcium oxide and carbon dioxide, like this: CaCO3(s)→CaO(s)+CO2(g)
At a certain temperature, a chemist finds that a 9.0L reaction vessel containing a mixture of calcium carbonate, calcium oxide, and carbon dioxide at equilibrium has the following composition:
Compound Amount
CaCO3 25.3 g
CaO 14.9 g
CO2 33.7 g
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

The value of the equilibrium constant Kc for this reaction is 0.088

Explanation:

where,

x = given mass

M = molar mass

= volume of solution in L

Equilibrium concentration of =

Equilibrium concentration of =

Equilibrium concentration of =

The given balanced equilibrium reaction is,

The expression for equilibrium constant for this reaction will be,

Now put all the given values in this expression, we get :

big big big big big   bigbig big big big big big big big big big big big big big big big big big big big big big big big penis

i believe the answer is true.