How many moles are in 2.5L of 1.75 M Na2CO3

(a) Calculate the molarity of a solution of 0.25 mole of NaOH in 5.0 L of solution. ... of a HCl solution if 18.25 mL of the solution were required to titrate 1.75 g.

Explanation:

4.375 moles Na2CO3

Explanation:

Formula for molarity is;

M = n/V

Where;

M is molarity

n is number of moles

V is volume

Making n the subject we have;

n = VM

We are given;

M = 1.75 M

V = 2.5 L

Thus;

n = 2.5 × 1.75

n = 4.375 moles Na2CO3

4.375 moles Na2CO3

Explanation:

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i think it's c. i'm not sure but i think so.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.