If 16.4 g of oxygen gas react with excess hydrogen, how many moles of water are produced? 2H2(g) + O2(g) → 2H2O(g)

1.02 (or 1.03 if rounded)

Explanation:

Given 16.4 grams of oxygen gas, you would want to write that down to set up your unit conversions.

16.4 g O2/1 * 1 mol of O2/31.998 g O2 * 2 mol H2O/1 mol O2

Multiply the numbers on the top and divide that by the product of the numbers on the bottom.

16.4 * 1 * 2 = 32.8

1 * 31.998 * 1 = 31.998

32.8/31.998 = 1.025...

Don't forget to consider the number of significant figures if it asks!

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