If a sample contains 70.0 % of the R enantiomer and 30.0 % of the S enantiomer, what is the enantiomeric excess of the mixture?

the enantiomeric excess of the mixture is 40%

Explanation:

The computation of the enantiomeric excess of the mixture is shown below:

As we know that

Hence, the enantiomeric excess of the mixture is 40%

i look it up online and i'll tell you

fr8t7iot7o87oglgt87ot79p0[90