2H2(g)+O2(g)→2H2O(l) What is the mass of water, H2O(l) , produced when 5.70 g of O2(g) reacts with excess H2(g)?

6.4g

Explanation:

32g of O2 produce 36g of H2O/5.70g of O2 produce x the answer is 6.4g

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