Suppose that a person eats a diet of 2388 Calories per day. Convert this energy into joules.
Convert this energy into kilojoules.
Convert this energy into kilowatt-hours.

9991 J

9.991 kJ

2.78 × 10⁻³ kWh

Explanation:

Step 1: Given data

Energy consumed per day by a person (E): 2388 cal

Step 2: Convert "E" to J

We will use the conversion factor 1 cal = 4.184 J.

2388 cal × 4.184 J/1 cal = 9991 J

Step 3: Convert "E" to kJ

We will use the conversion factor 1 kJ = 1000 J.

9991 J × 1 kJ/1000 J = 9.991 kJ

Step 4: Convert "E" to kWh

We will use the conversion factor 1 kWh = 3600 kJ.

9.991 kJ × 1 kWh/3600 kJ = 2.78 × 10⁻³ kWh

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante

4d^55s^1 ( third choice)