C3H8 (g) + 4C12 (g) → C3H4Cl4 (g) + 4HCI (g) Molar masses listed for the above equation:
C3H8 (g) = 44.1 g/mol
Cl2 (g) = 70.9 g/mol
C3H4Cl4 (g) = 181.9 g/mol
HCI (g) = 36.458 g/mol
A 4.00 mol sample of C3H8 (g) and a 6.00 mol sample of Cl2 (g) are placed in a previously
evacuated vessel, where they react according to the equation above. After one of the
reactants has been totally consumed, how many moles of HCI (g) have been produced?

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

b.false that your answer