Answer the following question:

A student wants to make a 2.50 M aqueous solution of silver nitrate, AgNO3 and has a bottle containing 21.89 g of silver nitrate. What should be the final volume of the solution?

Find the numerical answer for this question and make sure to include the following:

What is the formula for molarity?
What is the molar mass for silver nitrate?
When you give your numerical answer, what is the correct significant figures and how do you know that is the correct amount?

0.052L

Explanation:

Molarity of a substance, which refers to the molar concentration, is calculated as follows:

Molarity (M) = number of moles (mol) ÷ volume (L)

Mole = mass ÷ molar mass

Molar Mass of AgNO3 since Ag = 108, N = 14, O = 16

108 + 14 + 16(3)

= 108 + 14 + 48

= 170g/mol

Mole = 21.89 g ÷ 170g/mol

Mole = 0.129moles

Using Molarity (M) = number of moles (mol) ÷ volume (L)

Volume = number of moles ÷ molarity

V = 0.129 ÷ 2.50

V = 0.0516

To the correct significant figure i.e. 4s.f, the numerical value of volume = 0.052L

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