Iron (III) oxide is formed when Iron combines with oxygen in the air. How many grams of Fe₂O₃ are formed when 16.7 grams of reacts completely with oxygen? 4Fe + O₃ ---> 2Fe₂O₃

23.9g of Fe₂O₃ are produced

Explanation:

Are formed when 16.7g of Fe reacts completely...

Based on the reaction:

4Fe + O₃ → 2Fe₂O₃

4 moles of Iron react per 1 mole of O₃ producing 2 moles of Fe₂O₃.

To solve this question we need to convert the mass of iron to moles. The ratio of reaction is 2:1 -That is, 2 moles of Fe produce 1 mole of Fe₂O₃-. Thus, we can find the moles of Fe₂O₃ produced and its mass:

Moles Fe -Molar mass: 55.845g/mol-:

16.7g Fe * (1mol / 55.845g) = 0.299 moles of Fe

Moles Fe₂O₃:

0.299 moles Fe * (2 mol Fe₂O₃ / 4 mol Fe) = 0.150 moles Fe₂O₃

Mass Fe₂O₃ -Molar mass 159.69g/mol-:

0.150 moles Fe₂O₃ * (159.69g / mol) =

the answer is b & c i believe : )