At room temperature and pressure 14.2 g of chlorine will occupy what volume of gas

9.6

Explanation:

Volume at room temperature & pressure = no. of moles × 24

No. of moles = mass ÷ mass of 1 mole

= 14.2 ÷ 35.5

= 0.4 moles

Volume = 0.4 × 24 = 9.6

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.