A population of bacteria is growing according to the model P = 100 e .60t , where P is the number of colonies and t is measured in hours. After how many hours will 400 colonies be present? Round to the nearest tenth. Use LaTeX: A=pe^{rt}A = p e r t Group of answer choices

About 2.3 hours

About 0.6 hours

About 4.6 hours

About 8.5 hours

The answer is 2.3

Explanation:

The model for the population of bacteria is growing by

P= 100 x e^.60t

where P is the number of colonies and t is measured in hours.

Now, we need to find after how many hours will 400 colonies be present

So, Putting value of P = 400 in the above model and obtain the value of t

-> 400 = 100 x e ^.60t

-> 4 = e^.60 t

Take the natural log of ln on both sides

--> ln 4 = ln e ^.60 t

--> ln 4 = .60t

t= ln 4 / .60

T= 2.3

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.