Determine the density of nh3 gas at 435k and 1.00atm

We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

PV=nRT 

We manipulate this equation to give us an expression which will correspond to density. We do as follows:

PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
Density = 0.48 g / L

Where is the graph ?

Density and pressure