3) Une réaction de neutralisation est une réaction chimique entre une solution aqueuse acide et une solution aqueuse basique.
On effectue la réaction de neutralisation entre 100 mL d'une solution de HCl 0,5
mol/L à 19,7°C et 25 ml d'une solution de NaOH 2 mol/L à 19,7°C également dans un
calorimètre. On néglige l'énergie absorbée par les parois. On considère que la chaleur
massique de la solution est celle de l'eau pure et que la masse volumique des
solutions vaut 1kg/L.
La température finale mesurée dans le calorimètre est de 24,8°C.
Calculer la variation d'enthalpie molaire de cette réaction de neutralisation et
concluez quant au caractère endo ou exothermique d'une réaction de neutralisation.

please help

(1.6 × 10-19)(5.0 × 106) = c × 10d identify the missing numbers below to show the result of multiplying the numbers.

Which explanation is true about what happens to a ray of light when it strikes a mirror? a. a light ray is transmitted toward a mirror at a certain angle. the light ray is then reflected by the mirror at an equal angle but in the opposite direction of the transmitted ray. b. an incident ray strikes a mirror at an angle with a line perpendicular to the mirror. the light ray is then reflected at an angle equal to the angle of incidence but on the opposite side of the perpendicular line. c. a reflecting ray strikes a mirror at an angle with a line perpendicular to the mirror. the light ray is then refracted at an angle equal to the angle of the reflecting ray and on the same side of the perpendicular line. d. an incident ray strikes a mirror at an angle with a line parallel to the mirror. the light ray is then transmitted at an angle equal to the angle of incidence but on the opposite side of the parallel line. you so much! : -d take the time to try and answer correctly.

For the reaction shown, calculate how many moles of no2 form when each of the following completely reacts. 2n2o5(g)→4no2(g)+o2(g) part a 1.0 mol n2o5 express your answer using two significant figures. nothing mol m o l request answer part b 5.4 mol n2o5 express your answer using two significant figures.