Chemistry, 25.02.2021 01:20 CoolDudeTrist

Step 1: 2A⟶B+C slow Step 2: B+C⟶E fast Overall: 2A⟶E Determine the rate law for the overall reaction, where the overall rate constant is represented as .

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Answer from: mahdy43

R=k[A]^2

Explanation:

Steps mention in question are as follow.

Step 1: 2A <> B ( fast)

Step 2: B + C > D (slow)

Overall: 2A + C > D

The slowest step is as follows

2A <> B

Since the rate law is written as concentrations of reactants raised to power their stoichiometric coefficient multiplied by rate constant. Thus, rate law for this reaction can be written as follow.

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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Step 1: 2A⟶B+C slow Step 2: B+C⟶E fast Overall: 2A⟶E Determine the rate law for the overall reaction...