1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride? HF + NaNO3 -> HNO3 + NaF

1.096g

Explanation:

You must know the atomic mass of Hydrogen, Fluorine, and Sodium before you can start:

Hydrogen: 1.008g/mol

Fluorine: 18.99g/mol

Sodium: 22.98g/mol

Next, find the composition percentage of NaF

22.98 + 18.99 = 41.97

Fluorine is 18.99/41.97 =45.25%

Sodium is 100-45.25 = 54.75%

Ultimately we want to know about HF so find how much F is in 2.3g: 2.3 * 0.4525 = 1.041g

Find comp. percentage of HF

18.99+1.008 = 19.998; H/total F/total

Hydrogen 5.041%

Fluorine 94.959%

Laws of conservation of say we have 1.041g of fluorine in our HF. We know 1.041 is 94.959% of the mass of HF so do some simple math to find the remaining: 1.041/0.94959 = 1.096g

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environmental implications of pesticides

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health implications of organics

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health implications of pesticides

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other important considerations

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