PLS HELP THIS IS DUE IN 30 MINS ANSWER BOTH QUESTIONS PLS AND TY

1. Cl electron configuration: 1s^2 2s^2 2p^6 3s^2 3p^5

Ag electron configuration: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^9

2. It will be easier to remove beryllium's valence electrons. Beryllium has two valence electrons, while oxygen has six valence electrons. This means that oxygen has a greater attraction on its electrons because the protons and electrons are closer together. Moreover, during bonding, beryllium is more likely to form the cation Be^2+ and oxygen is more likely to form the anion O^2-. This shows that due to beryllium's weaker attraction, it is more likely to get its electrons taken away than oxygen is.

Explanation:

1. Complete each of the orbitals up to each of the desired elements. Look up a diagram showing the electron shells of the periodic table and count the electrons of each element to be able to solve any configuration problem.

Another way of writing the answer would be in noble gas configuration. This would change the answer to:

Cl: [Ne] 3s^2 3p^5

Ag: [Kr] 5s^2 4d^9

But both answers (the extended electron configuration and the noble gas configuration) mean the same thing.