How much carbon dioxide will be formed if 12.5 grams of oxygen reacts with 7.2 grams of propane?

66 grams of Carbon Dioxide.

Explanation:

The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams.

C 3 H 8 + 5 O 2 = =3 C O 2 + 4 H 2 O

This is the balance equation for the burning of propane in Oxygen.

From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3

Convert 22 grams of propane to moles by dividing by the molar mass of propane.

3 x 12 = 36 grams

1 x 8 = + 8 grams

total = 44 grams/ mole.

22

44

= .5 moles of propane.

Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide.

Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide

1 x 12 = 12 grams

2 x 16 = +32 grams

total = 44 grams /mole.

1.5 moles x 44 grams/mole = 66 grams.

hope that helps :)