6.12 moles of Na3PO4 experimentally produced 1001g of sodium chloride according to the equation below. What is the percent yield?

2Na3PO4 + 3 CaCl2 --> Ca3(PO4)2 + 6NaCl

155.5%

Explanation:

from the equation

2mol of Na3PO4 reacts to give 6mol of Nacl

therefore 6.12mol of Na3PO4 will give 18.36mol of Nacl

2mol Na3PO4 6mol of nacl

6.12mol NaPO4 6×6.12mol/2mol = 18.36mol of Nacl

mass of Nacl = mol × molar mass

where molar mass of Nacl= 23+12=35g/mol

mass of Nacl= 18.36 × 35= 642.6g of Nacl

percentage yield = actual yield/ theoretical yield ×100%

percentage yield= 1001g (given)/642.6g(used) ×100 = 155.5%

107%

Explanation

6.12 mol Na3Po4 | 6 mol NaCl | 58.44 g NaCl

= 1072g NaCl

                              | 2 mol Na3Po4 | 1 mol NaCl

1072g/1001g x 100= 107%

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

c (diamond),

sio2 (quartz)