When you mix two substances, the heat gained by one substance is equal to the heat lost by the other substance. Suppose you place 125 g of aluminum in a calorimeter with 1,000 g of water. The water changes temperature by 2 °C and the aluminum changes temperature by –74.95 °C. Water has a known specific heat capacity of 4.184 J/g °C. Use the specific heat equation to find out how much heat energy the water gained (q). Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)

So heat required to raise the temperature of water is given as Q = 33472 J

Explanation:

As we know that the temperature of water is increased by 2 Degree C

So here we have heat gain by the water is given by the equation

Q = m s\Delta TQ=msΔT

Now we know that

m = 1000 g

s = 4.184 J/g C

Now plug in all data in above equation

Q = 1000(4.184)(2)Q=1000(4.184)(2)

Q = 33472 JQ=33472J

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explanation:

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