2NH3+2O2- N2O+3H2O If 80.0 grams of O2 reacted in above reaction ,how many grams of N2O will be produced?

55.0125 grams NO2

Explanation:

So we have 80 grams of O2, first convert to moles

80 g O2 * 1 mol/32 g O2 = 2.5 mol O2

Next use the mole ratio of O2 to NO2

2.5 mol O2* 1 mol NO2/2 mol NO2=1.25 mol NO2

Since the question is asking how many grams, convert NO2 to grams

1.25 mol NO2 * 44.01 NO2/1 mol NO2= 55.0125 grams

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