Draw the major organic product in the reaction scheme. Be sure to clearly show stereochemistry (if applicable).The starting material is an alkyne where carbon 1 is bonded to cyclopentane and carbon 2 is bonded to H. Step 1 is N a N H 2. Step 2 is C H 3 I. Step 3 is sodium in liquid ammonia.

See explanation below

Explanation:

According to what you state in the problem, we have an ethyne bonded to a cyclopentane.

So, in the 1st step reacts with NaNH₂. In this step, the base which is very strong will substract the hydrogen from carbon 2, forming an anion in there. In the second step, this anion will react with  CH₃I, and form a larger chain, the methyl group is attached to the alkyne.

Finally in the last step reacts with sodium in ammonia, this is to reduct the triple bond to just a single bond and leave an alkane only. The picture below shows these steps.

Hope this helps.

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