Please help Imagine a made up polyatomic ion called tritoborate. Calcium tritoborate has the formula Ca2B3O8. a. What is the formula for tritoborate? You must include the charge (both the sign and the
magnitude). (2 pts)

b. Write both the formula and the name for the compound formed when Fe3+ combines
with tritoborate? (2 pts)

a. The formula for tritoborate ion is B₃O₈²⁻

b. The formula of the compound formed will be Fe₂(B₃O₈)₃ and the name will be Iron (iii) tritoborate

Explanation:

The formation of compounds by atoms of elements occurs in accordance with the valencies of the elements. Valency refers to the combining power of an element. For metallic elements, it is usually the number of electrons they can give up or lose while for non-metallic elements, it is the number of electrons they can accept. The valency of an atom of an element is related to its oxidation number. Metals have positive oxidation numbers while non-metals have negative oxidation numbers. Sometimes, two or more atoms combine together and react as a single unit and may carry a positive or negative charge. These are known as a radicals. For example, ammonium ion, NH₄⁺.

In the given question, calcium tritoborate, CaB₃O₈ is formed from the combination of calcium ion and tritoborate ion. Calcium ion carries the charge of +2, therefore, the tritoborate ion must have a charge of -2 in order to form a compound since the overal charge on a compound is zero.

a. let the tritoborate ion be represented by X

Ca = +2, X = ?

+2 + X = 0

X = -2

Thus, the formula for tritoborate ion is B₃O₈²⁻

b. When tritoborate ion combines with iron (iii) ion, Fe³⁺, two moles of Fe³⁺ will be required to react with three moles of B₃O₈²⁻ in order to have a neutral compound. The formula of the compound formed will be: Fe₂(B₃O₈)₃ and the name will be Iron (iii) tritoborate

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: