For the reaction CH4+2O2=2H2O+CO2
How many moles of water are produced from the combustion of 45.2g of methane(CH4)?

45.2g produce x mole of CH4. we are given the mass of methane. mass (CH4)=45.2g. molar mass (CH4) = 12+4 =16g/mol. Mole=mass. molar mass. mole=45.2. 16. mole=2.8mol. therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol

Explanation:

45.2g produce x mole of CH4. we are given the mass of methane. mass (CH4)=45.2g. molar mass (CH4) = 12+4 =16g/mol. Mole=mass. molar mass. mole=45.2. 16. mole=2.8mol. therefore, if 45.2g produce 2.8mol as 1 mole of methane, the water produced is 2(2.8) we Are multiplying by 2 because the water is having 2 moles water mole is 5.6mol