A gas has a volume of 500cm3 when a pressure of 100,00N is exacted on it what will be it's volume if the pressure is changed to 150mm mecury at same temperature

See explanation below

Explanation:

At first sight, it seems that the innitial pressure of 100,00 N would be 100,00 N/m² because pressure does not have units of newton alone. If this is true, then the calculations are the following (If it's not, but it's actually mm Hg, then skip the part of the conversion, and just do the procedure of solving for the volume).

The innitial pressure is 100 N/m² or simply 100 Pa. As the second pressure is in mm Hg, let's convert the Pascal units to mm Hg:

1 Pa > 0.007501 mm Hg

100 > X

X = 100 * 0.007501 / 1 = 0.7501 mmHg

Now that we have the innitial pressure in mm Hg, and the temperature remains constant, we use the Boyle's law to solve for this:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂  

Using this expression, let's solve for V₂:

V₂ = 0.7501 *¨500 / 150

V₂ = 2.5 cm³

Now, it's the innitial pressure is 100 mm Hg then the volume:

V₂ = 100 * 500 / 150

V₂ = 333.33 cm³

Check the units of the innitial pressure, one of these results should be the correct answer. If it's not, then please post again the question with the correct units.

Hope this helps

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"