How many moles of ammonia (NH3) can be produced from 6.7 mol of H2 according to the following chemical equation? 3 H2 + N2 + 2NH3
Provide the answer with 2 or more significant figures.

4.5 moles of NH₃

Explanation:

Step 1: Write the balanced equation

3 H₂(g) + N₂(g) ⇒ 2 NH₃(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of H₂ to NH₃ is 3:2.

Step 3: Calculate the moles of NH₃ produced from 6.7 moles of H₂

We will use the previously established molar ratio.

6.7 mol H₂ × 2 mol NH₃/3 mol H₂ = 4.5 mol NH₃

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.