The radioisotope technetium-99 is often used as a radiotracer to detect disorders of the body. It has a half-life of 6.00 hours. If a patient received a 20.0 mg dose of this isotope during a medical procedure, how much would remain 24.0 hours after the dose was given?

Explanation:

= Half-life of technetium-99 = 6 hours

= Initial mass of sample = 20 mg

= Time elapsed = 24 hours

Amount of mass remaining is given by

The amount of the sample that would remain is .

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.