In the laboratory, a general chemistry student measured the pH of a 0.313 M aqueous solution of acetylsalicylic acid (aspirin), HC9H7O4 to be 2.031. Use the information she obtained to determine the Ka for this acid.

for the acid is

Explanation:

   c             0             0

So dissociation constant will be:

Give c= 0.313 M and = 2.031

Also

[   

Putting in the values we get:

for the acid is

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2