Calculate the mass of water produced from the reaction of 24.0 g of H2 and 160.0 g of O2. What is the limiting reagent?

  is the limiting reagent, 180 g of water is produced

Explanation:

To calculate the moles :

According to stoichiometry :

1 mole of require 2 moles of

Thus 5 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 1 mole of give = 2 moles of

Thus 5 moles of give =  of

Mass of

Thus 180 g of will be produced from the given masses of both reactants.