A careless student forgets to label one of their reagent containers. They know it contains one of the following solutions: 0.1 M NaCl 0.1 M Ca(NO3)2 0.1 M KCH3COO The student decides to add some 0.1 M Pb(NO3)2 to a sample of the reagent in question. Upon stirring, a white precipitate formed. Which of the possible solutions is present in the unlabeled container based on this observation? A. 0.1 M KCH3COO
B. 0.1 M Ca(NO3)2
C. 0.1 M NaCl

0.1 M NaCl

Explanation:

This question reminds of of the solubility rules. Let us recall that all chlorides are soluble except those of lead, mercury II and silver which are insoluble in water.

The following reaction will occur leading to the formation of a precipitate;

Pb(NO3)2(aq) + 2NaCl(aq) > 2NaNO3(aq) + PbCl2(s)

The white precipitate formed is  PbCl2.

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

i'm assuming that it's c.) red bank..