How many joules of heat energy are absorbed when 80.0 g of water are heated from 10.0°C to 50.0°C? *

13440 J

Explanation:

c ≈ 4200 J / (kg * °C)

m = 80 g = 0,08 kg

= 10 °C

= 50 °C

The formula is: Q = c * m * ()

Calculating:

Q = 4200 * 0,08 * (50 - 10) = 13440 (J)

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.