Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 14. g of hydrochloric acid is mixed with 6.55 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.

8.02 g of HCl could be left over by the chemical reaction

Explanation:

We propose the reaction:

HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)

Ratio is 1:1. First of all, we determine the moles of reactants:

14 g . 1mol / 36.45g = 0.384 mol of acid

6.55 g. 1mol / 40g = 0.164 mol of base

If a determined mass of HCl, could be left; this means that the acid is the excess reagent.

For 0.164 moles of NaOH, we need 0.164 moles of HCl.

As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:

0.220 mol . 36.45 g /1mol = 8.02 g

- lead + phosphoric acid = hydrogen + lead(ii) phosphate