6 NaOH + 2 Al ---> 2 Na3AlO3 + 3 H2 1. How many grams of Na3AlO3 can be formed from 165.0 g of NaOH?
2.How many moles of NaOH are required to produce 3 g of H2
3. How many moles of H2 can be produced from 1.5 moles of Al?
4. How many grams of NaOH will you need to produce 2.4 moles of Na3AlO3?
5.How many moles of Al would be required to produce 4.4 moles of Na3AlO3?

note: can you also show me how you got the answer please.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

c, liquids evaporate, creating a gas

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml