The Kc (equilibrium constant)at a particular temperature for the reaction: H2(g) + Br2(g)↔ 2HBr(g) is 1.5 ×105.

What is the value of Kc for HBr(g) ↔ ½ H2(g) + ½ Br2(g) ?

What is the value of Kc for HBr(g) ↔ ½ H2(g) + ½ Br2(g) ?

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

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може ли да зареждате повече информация, моля

50.23 i believe is correct but don't quote me on that.