A balloon with a volume of 0.5L at 293K is cooled to 20K. What is the balloon's new
volume?

0.03 L

Explanation:

Step 1: Given data

Initial volume of the balloon (V₁): 0.5 LInitial temperature of the balloon (T₁): 293 KFinal volume of the balloon (V₂): ?Final temperature of the balloon (T₂): 20 K

Step 2: Calculate the final volume of the balloon

The balloon is filled with air. If we assume it behaves as an ideal gas, we can calculate the final volume of the balloon using Charles' law.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 0.5 L × 20 K/293 K = 0.03 L

4- c, because all matter stays the same no matter what. it is still there. 5- b, because matter is known as mass. 6-c because, flammability is a chemical property. malleability is changing the shape of an object.

Ans. : frostbite is when exposure to cold temperatures causes freezing to the skin or other tissues. it most commonly affects the hands, feet, and face. the longer areas are exposed to cold, typically the worse the frostbite. the water temperature used for rewarming a frostbitten part should be : (102 -105) f degrees.